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Lemma Inequality For The Sum of Cubes of Two Terms

Posted on May 4, 2026May 4, 2026 by Chase

Lemma. If $a, b \geq 0$, then $a^3 +b^3 \geq a^2 b + a b ^ 2$. Proof. Since $a,b\geq 0$, $a+b\geq 0$. Also, by the trivial inequality, $(a-b)^2 \geq 0$. Thus, $(a-b)^2 (a+b)\geq 0$. Expanding, $a^3 + b^3 – a^2 b – a b^2 \geq 0$. So, $a^3 +…

Posted in MathTagged Algebra, Lemma, ReviewLeave a Comment on Lemma Inequality For The Sum of Cubes of Two Terms

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